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arsen [322]
3 years ago
12

Over time, smart phones have become _____.

Computers and Technology
2 answers:
-BARSIC- [3]3 years ago
7 0
I think the answer is the 2nd one
Fynjy0 [20]3 years ago
5 0

Answer:

C. Less expensive for a certain amount of computing power.

Explanation:

Overtime, smartphones have become less expensive for a certain amount of computing power but easier to use.

Smartphones are more than just a way to reach out to people, they have a lot of features aside from calling and texting.

Basically, smartphones have high-speed internet accessibility, high definition digital cameras, games, text-to-speech app, GPS and a variety of fun social media applications for the Apple iOS and Android operating system.

Hence, with the above-mentioned features it performs all sort of tasks seamlessly to the satisfaction of the users with easy commands.

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(5 points) Create a user-defined data structure (i.e., struct) called Point that represents a two-dimensional Cartesian coordina
Harlamova29_29 [7]

Answer:

Here is the C++ program:

#include<iostream>  //to use input output functions

#include <math.h>  //to use sqrt and pow function

#include<iomanip>  //to use setprecision

using namespace std;   //to identify objects cin cout

struct Point  {  // structure name

float x,y;  // member variables

};  

float calculateDistance (Point a, Point b)  {  //function that that takes two parameters of type Point

float distance;  //stores the distance between two points

distance=sqrt(pow(a.x-b.x,2)+pow(a.y-b.y,2));  //formula to compute distance between two points

return distance;  }  //returns the computed distance

int main()  {  //start of main function

Point p1,p2;  //creates objects of Point

cout<<"Enter point 1 coordinates: "<<endl;  //prompts user to enter the value for coordinates of first point

cin>>p1.x;  //reads input value of x coordinate of point 1 (p1)

cin>>p1.y;  //reads y coordinate of point 1 (p1)

cout<<"Enter point 2 coordinates: "<<endl;  //prompts user to enter the value for coordinates of second point

cin>>p2.x;  //reads input value of x coordinate of point 2 (p2)

cin>>p2.y;  //reads y coordinate of point 2 (p2)

cout<<"The distance between two points is "<<fixed<<setprecision(2)<<calculateDistance(p1,p2);} //calls function by passing p1 and p2 to compute the distance between p1 and p2 and display the result (distance) up to 2 decimal places

Explanation:

The program has a structure named Point that represents a two-dimensional Cartesian coordinate (x, y). The member variables of this struct are x and y, which are both floating-point values. A function called calculateDistance takes two parameters, a and b of type Pointer and returns the distance between the two given points using formula:

\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

It uses pow function to compute the power of 2 and sqrt function to compute the square root.

Then in main() method the program prompts the user to enter coordinates for two points and calls calculateDistance method to compute the distance between two points and display the result up to 2 decimal places using setprecision(2).

The program along with the output is attached in a screenshot.

6 0
3 years ago
Write a function (subroutine) that inputs a data value in register r0 and returns value in r0. The function returns y 5 a 1 bx 1
umka2103 [35]

Solution :

  int f(int x){

      \text{return a + b*x +c*x*x};

  }*/

  int f(\text{int R0}){

      int stack[2] = {\text{R1,R2}};

      \text{R1 = R0};

      \text{R1 = R1}\times \text{ R1};

      \text{R2 = C};

      R1 = R1 * C; /*R1 = cx^2*/

      \text{R2 = B};

      \text{R0 = R0} * R2; /* R0 = bx */

      \text{R0 = R0 + R1}; /*R0 = bx + cx^2 */

      \text{R2 = C};

      \text{R0 = R0 + R2}; /*R0 = a+bx+cx^2 */

      \text{R1 = stack[0];}

     \text{ R2 = stack[1];}

     \text{ return R0;}

  }

  /*\text{ARM code to implement the following C operation}

  int s=0;

  \text{for ( i = 0; i < 10; i++)}

  { \text{s = s + i } \times i;)

  */

          AREA SumSquares, code, readWrite

          ENTRY

          \text{MOV r0, #0}        ;loop \text{ counter i present at 0}

          MOV r1, #0       ; s = 0

  Loop   \text{MUL r2, r0, r0}   ;calculate i*i

          \text{ADD r1, r1, r2}   ;s = s+ i*i

          \text{ADDS r0, r0}, #1   ; i = i+1

          \text{CMP r0},#10       ; test for end

          \text{BNE} Loop        ; \text{continue until all added}

          END

5 0
3 years ago
To apply the rule of thirds you first? PLZ HURRY AND ANSWER THIS
Deffense [45]
B/ Divide the viewpoint into three equal vertical divisions
5 0
4 years ago
Read 2 more answers
Given a scanner reference variable named input that has been associated with an input source consisting of a sequence of strings
Makovka662 [10]

The code that examines all the strings in the input source and determines how long the longest string (or strings are) is the following:

total = 0; % initial value is zero, in every while loop it will be incremented

while(input.hasNextInt()){

total += input.nextInt( );

}

7 0
3 years ago
Read 2 more answers
PLEASE HELP PROGRAMMING WILL GIVE BRAINLIEST
DaniilM [7]

Answer:

1. would be B.

2. would be D

3. May I ask if it can be multiple answers?

Explanation:

1. In coding a if statement has to follow if something is true or not. If we are talking about a if and then statement it will skip that block and move to the next block of the "then" part of the "if then" Statement if the first part is reported false

2. This is a easy one, so it has to be either a 3.25 GPA or higher or they have to have either 100 hours or more.

3. waiting for a comment back :)

4 0
4 years ago
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