Question

2. Find the area of the regular polygon. Give the answer to the nearest tenth. Hexagon with a radius of 5 in.

Answer 1

$360 \div 6 = 60 \\ 60 \div 2 = 30 \\ \frac{1}{2} (2.5 \sqrt{3} )(5) \\ 6(6.25 \sqrt{3} ) = 65.0$
Answer for #2 is A

3. D

Answer 2

Answer:  The correct options are (2). A,  (3). A.

Step-by-step explanation:  The calculations are as follows:

(1) We are to given the area of a regular hexagon with radius 5 in.

The AREA of a regular hexagon with side  'a' units is given by

$A=\dfrac{3\sqrt3}{2}a^2.$

We know that the radius of a regular hexagon is equal to the length of each side, so we have

a = 5 in.

Therefore, the area of the hexagon will be

$A=\dfrac{3\sqrt3}{2}\times 5^2=1.5\times 1.732\times 25=64.95\sim 65~\textup{in}^2.$

Thus, (A) is the correct option.

(2) Given that two adjacent sides of the triangle measure 1.32 miles and 2.75 miles.

The angle lying between the two sides measure 35°.

we are to find the area of the triangle.

We know that the area of a triangle with two adjacent sides of measure 'a' and 'b' units and 'β' be the measure of the angle lying between them is given by

$A=\dfrac{1}{2}ab\sin \beta.$

Here, a = 2.75 miles,  b = 1.32 miles  and  β = 35°.

Therefore, the total search area, in the form of triangle is given by

$A=\dfrac{1}{2}\times 2.75\times 1.32\times \sin 35^\circ=1.815\times 0.5735=2.08~\textup{mi}^2.$

Thus, the correct option is (A) 2.08 mi².

Hence, the correct options are (2). A,  (3). A.