Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Step-by-step explanation:
vertex form is y=a(x-h)^2 + k
here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.
so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.
now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have
-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a
the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Answer: 1.23×10¹⁶
Step-by-step explanation:
For this problem, we want to use order of operations to solve.
Parenthesis
Exponent
Multiply
Divide
Add
Subtract
Let's first solve the parenthesis.
[add denominator]
[cross multiply]
[divide]
[exponent]
1.23×10¹⁶
The ending result is way too large. Therefore, we use scientific notation and get 1.23×10¹⁶.
To Prove :
Side lengths 6, 8 and 10 will make a right triangle.
Solution :
We know, by Pythagoras theorem :
Here, c is the biggest side and a and b are other sides.
Putting given values in above equation.
Since, LHS = RHS .
Therefore, lengths 6, 8 and 10 will make a right triangle.
If you put the indefinite integral into Y1 for a graph and then place as many numbers in L1(The more the better) and then go into "VARS", "Y-VARS", "FUNCTION" and select "Y1". Then use "Y1(L1)sto>L2" to find all Y values of the indefinite integral and use a regression command to give the equation for the Indefinite Integral.EX:Y1=∫0x(3x^2)dx
L1={−10,−9,−8,−7,−6,−5,−4,−3,−2,−1,0,1,2,3,4,5,6,7,8,9,10}
Y1(L1)→L2
CubicReg using L1 as Xlist and L2 as Ylist
y=ax^3+bx^2+cx+da=1b=0c=0d=0
y=x3
