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jolli1 [7]
3 years ago
13

Find the slope of the line through the points (3,2) and (4,5).

Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

<h2>The answer is 3</h2>

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1}  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question we have

m =  \frac{5 - 2}{4 - 3}  =  \frac{3}{1}  = 3 \\

We have the final answer as

<h3>3</h3>

Hope this helps you

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Find the simultaneous equation x-2y=1,y^2-3xy+8=0​
Hitman42 [59]

Answer:

  (-2.2, -1.6), (3, 1)

Step-by-step explanation:

You don't have to go far to find the equations. They are right there in your problem statement. Perhaps you want to find the solutions to the equations.

Use the first equation to write an expression for x, then substitute that into the second equation:

  x = 2y +1

  y^2 -3(2y+1)(y) +8 = 0

  -5y^2 -3y +8 = 0

  -(5y +8)(y -1) = 0

  y = -8/5   or   y = 1

The corresponding values of x are ...

  x = 2(-8/5)+1 = -11/5

  x = 2(1) +1 = 3

The solutions are (x, y) = (-2.2, -1.6) and (3, 1).

5 0
2 years ago
A storekeeper has two kinds of flour, one selling for 65 cents per pound, and the other selling for 95 cents per pound. How many
Murrr4er [49]

Answer:

The amount of 65 cents per pound flour to use is 40 pounds and the amount of 95 cents per pound flour to use is 60 pounds

Step-by-step explanation:

Let

x ----> amount of 65 cents per pound flour to use

y----> amount of 95 cents per pound flour to use

we know that

x+y=100 ----> y=100-x ----> equation A

0.65x+0.95y=0.83(100) ----> equation B

substitute equation A in equation B

0.65x+0.95(100-x)=0.83(100)

Solve for x

0.65x+95-0.95x=83

0.95-0.65x=95-83

0.30x=12

x=40\ lb

Find the value of y

y=100-40=60\ lb

therefore

The amount of 65 cents per pound flour to use is 40 pounds and the amount of 95 cents per pound flour to use is 60 pounds

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3 years ago
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mafiozo [28]

Answer:  621

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2 years ago
A:1 hour 37 minutes <br> B:2 hours 37 minutes <br> C:2 hours 23 minutes <br> D:1 hour 23 minutes
Y_Kistochka [10]
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