What is the product? PLSS HELP!!

Emily and Holly took a road trip together. Emily drove at an average of 45 miles per hour for the first 3/7 of the total distanc

Elan Coil [88]

Emily drove 3/7 of the total distance and holly drove the rest which explains that holly drove 4/7 of the whole distance.

if 4 parts of the distance equals 24 miles, then 1 part would be 24/4 is 6.
since emily drove 3 parts of the whole distance, it is 6 × 3 = 18 miles.

travelling time of emily = 18/45 = 0.4 hr
travelling time of holly = 24/54 = 0.4 hr
--> total traveling time = 0.8 hr

i hope it is right

3 0

3 years ago

In Youngtown, the population reached 4420 people in 1993. In 1998, there were 5600 residents. What was the population in the yea

Ede4ka [16]

<span>Growth rate = (Present - Past)/Past Plugging in what we know Growth rate =(5600â’4420)/4420 Thus Growth rate=.26697 Now we can plug the growth rate into our first formula which gives us P=5600e^(.26697â‹…2) Solve for P and we get P = 9551.58 however since you can not have .58 of a person we round down to 9551. So Youngtown will have 9551 citizens in the year 2000</span>

6 0

3 years ago

What is the gradient of the blue line

nirvana33 [79]

Answer:4

Step-by-step explanation:

When you look at the two lines, you can see that the blue line is steeper than the red line. It makes sense the value of the slope of the blue line, 4, is greater than the value of the slope of the red line, 14 .

4 0

2 years ago

Read 2 more answers

An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume

Lynna [10]

Answer:

a) $21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

b) $ME=2.58\frac{52}{\sqrt{350}}=7.17$

c) $ME=2.58\frac{52}{\sqrt{100}}=13.42$

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$\bar X=21$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=52$ represent the population standard deviation

n=350 represent the sample size

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$