Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
<em>Look Below In the Explanation</em>
Step-by-step explanation:
Point P has coordinates of (4,4) and point Q has coordinates of (4,-4).
Since both points have the same x-coordinates we can subtract point Q's y-coordinate from point P's y-coordinate.
I will set the equation up and try and figure this part by yourself. I hope you learned what to do from previous questions that are very similar to this that I answered.
4 - ( -4) = length of the bed of flowers
Hope that helps and maybe earns a brainliest!
Have a splendid day! :^)
Answer:106.
Step-by-step explanation:
