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3 years ago

Three times a number is the same as five more than twice the number

2 answers:

7 0

3x (three times a number) = (is the same as) 5 + (five more than) 2x (twice the number)

or, 3x = 5+2x
then subtract 2x from both sides: x = 5

Which should make sense, three times 5 is 15. 5 plus two times 5 is also 15.

Alenkasestr [34]3 years ago

5 0

Ok so first lets make the equation
3x=5+2x
we subtract 2 on each side
x=5

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A bike rental shop charges a 13 dollar fixed fee plus 7 dollars an hour for renting a

Verdich [7]

Answer:

vRead the passage from “The Beginnings of the Maasai.”

Now Enkai lives at the top of Mount Kenya, and we Maasai still live below, herding cattle down in the plains. It’s not a bad life, especially when Enkai is the Black God, providing for us. And when the cattle or other children cause problems, I just warn them that they never know when I might suddenly develop my godly powers.

The main purpose of the passage is to illustrate the relationship between the Maasai and

Mount Kenya.

the children.

the cattle.

their god.

Step-by-step explanation:

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2 years ago

Read 2 more answers

Which value of x is in the domain of f(t) = squared x - 7

zloy xaker [14]

Given:

The given function is:

$f(x)=\sqrt{x-7}$

To find:

The value of x that is in the domain.

Solution:

Domain is the set of input values.

We have,

$f(x)=\sqrt{x-7}$

We know that the square root is defined for non negative values. So,

$x-7\geq 0$

$x\geq 0+7$

$x\geq 7$

Thus, the domain of the given function is all real number that are greater than or equal to 7.

In the given options 0, -3, 6 are less than 7 but 8 in option A is the only value that is greater than 7. So, $x=8$ is in the domain of the given function.

Therefore, the correct option is A.

8 0

2 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$