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viva [34]
3 years ago
8

Linda enrolls for 10 credit-hours for each of two semesters at a cost of $500 per credit-hour (tuition and fees). In addition, t

extbooks cost $300 per semester. Round your answer
Mathematics
1 answer:
kodGreya [7K]3 years ago
3 0
I agree with the other answer
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5. A cabin rental costs $100 deposit plus $75 per day. Find the cost of renting a cabin for the
Alik [6]

Answer:

the answer to this question is $2,350

Step-by-step explanation:

june has 30 days so $75 × 30 + $100 = $2,350

6 0
2 years ago
Can someone do these questions 1-3 please i have an F in math now :/
ruslelena [56]

Answer:

There is no picture.

Step-by-step explanation:

4 0
2 years ago
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Please help me if you know<br> it means a lot thank you
max2010maxim [7]

1.5 x -3 +4. x=-3

-15+4

-11

2.-4/4-2 x-4-3. y=-4

-1-+8-3

7-3

4

6 0
3 years ago
Is 5 a solution to the compound inequality “-3 &lt; x &lt; 6”
Naddika [18.5K]

Answer:

The possible answers are  

-2,-1,0,1,2,3,4 and 5

3 0
3 years ago
A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

                                = 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

\frac{\alpha}{2} = \frac{0.05}{2}

  = 0.025

Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

                           = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

3 0
3 years ago
Read 2 more answers
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