Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
I think it would have to be 1.46.
Explanation: if you subtract 3.56 from 2.1 you’ll get 1.46
Answer:
x=5
Step-by-step explanation:
esa es la respuesta correcta
** x + 5 = 7
x = 2
** x + 5 = 9
x = 4
{2,4}
I assume you're asking where it meets the y axis
In an equation the last number is the y intercept so I'm this case it would be 1
