Answer: The span of the bridge is 59.77ft
Step-by-step explanation:
The standard form of equation for an ellipse with vertical major axis is:
(x-h)^2/b^2+(y-k)^2/a^2=1,a>b, (h,k)=(x,y) coordinates of center.
For given problem:
Place center of ellipse, (0,0) at center of bridge at ground level.
Given length of vertical major axis=70=2a
a=35
a^2=1225
Equation of an ellipse with horizontal major axis with center at (0,0)
Equation of ellipse:
x^2/b^2+y^2=1
plug in coordinates of given point on ellipse(27, 15)
27^2/b^2+15^2/a^2=1
729/b^2+225/1225=1
729/b^2=1-225/1225= 0.816
b^2=729/0.816≈ 893
b≈29.88
length of minor axis=2b≈59.77 ft
span of bridge≈59.77 ft
1/2 of 40= 20
40/5=8
20+8=28
28 of your CDs will not work properly.
I hope this helps!
Answer:
2) k=17/45 and 4) 29/22
Step-by-step explanation:
Answer:6.48
Step-by-step explanation:
1.60 times 4 jus to start it off it will be 6.40 plus the 1/2 pound it will be .80 plus 6.40 will be 7.20 and 10 percent off that is .72 the remainder will be 6.48
