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olga2289 [7]
3 years ago
5

THE RIGHT ANSWER WILL RECIEVE A BRAINLEST AND POINTS AND THANXS!!!

Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0

Okay so heres what you gotta do.

You know that at store a it is $129 for 30%

So that means that you are paying 70%

Use this logic to solve for all of the real prices.

70%=.7

A)129*.7=$90.3

B).65*135=$87.75

C) 150*.6=$90

BUY FROM STORE B SINCE THE PRICE IS THE LOWEST.

irina [24]3 years ago
4 0
The frist one is the cheepist.
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Aneli [31]

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Phoebe has £180, Andy has £60, and Polly has £30.

Step-by-step explanation:

Ok, to start of let's establish some variables! We'll give Phoebe the variable "p", Andy the variable "a", and Polly the variable "o". By giving each person a variable we can create an equation and solve for it!

<em>So, what do we know?</em>

Well we know the following information...

<em>p + a + o = 270</em>

(Phoebe + Andy + Polly = £270)

<em>p = 3a</em>

(Phoebe = 3 times more than Andy)

<em>a = 2o</em>

(Andy = 2 times more than Polly)

To be able to solve this equation we have to solve for just one variable first.<em>The only one we can use is "o" for Polly!</em>

<em></em>

3(2o) + 2o + o = 270

6o + 2o + o = 270 (Distribute 3 to get like terms)

9o = 270 (Combine like terms [6+2+1])

o = 30 (Divide by 9 on both sides to get "o" by itself)

Now that we have how much Polly has, we have to solve for Andy and Phoebe. <em>(To do this we will input our value, 30, where our variable is "o")</em>

<em></em>

<u>Andy</u>

a = 2(30) (Input term)

a = 60 (Multiply by 2 to get final answer)

<em>(Since we now know what Andy has we can input 60 into our "a" variable to solve for Phoebe)</em>

<u>Phoebe</u>

p = 3(60) (Input term)

p = 180 (Multiply by 3 to get final answer)

Now! Just to check we are going to input our variables into our original equation to be sure we have the right variables.

p + a + o = 270

180 + 60 + 30 = 270!!

Hope this Helps! :)

<em>Have any questions? Ask below in the comments and I will try my best to answer.</em>

-SGO

<em></em>

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