Question

solve the equation using the Quadratic Formula. Round your solutions to the nearest tenth if necessary.) please help I need explanation I'm stuck on this I need your help please ​

Answer 1

Answer:

Quadratic Formula x = [-b +- Sq root (b^2 - 4ac)] / 2a

In this example a= 2 b= -6 c= 5

x = [- - 6 +- Sq root ((-6^2) - 4 *2*5)] / 2*2

x = [6 +-sq root (36 -40)] / 4

x = 6 +- 2i / 4

x1 = 1.5 + .5i  

x2 = 1.5 -.5i

Step-by-step explanation:

Answer 2

Answer:

x = 1.5 - .5i and 1.5 + .5i

Step-by-step explanation:

to start off - this is the quadractic fromula: x = -b ± √b²-4(a)(c) / 2(a)

a = 2x²

b = -6x

c = 5

now you just fill the numbers in to the formula!!

x = -(-6) ± √(-6)²-4(2)(5) / 2(2)

x = 6 ± √36 - 40 / 4

x = 6 ± √-4 /4

x = 6 ± 2i / 4

x = 6+ 2i/4     and 6 - 2i/4

x = 1.5 + .5i    amd 1.5 - .5i

hope this helps!!