Answer:
167.27 mg.
Step-by-step explanation:
We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.
We will use half life formula to solve our given problem.
, where N(t)= Final amount after t years,
= Original amount, t/2= half life in years.
Now let us substitute our given values in half-life formula.
![N(2000)=400*0.4181633028874878239](https://tex.z-dn.net/?f=N%282000%29%3D400%2A0.4181633028874878239)
![N(2000)=167.26532115499512956\approx 167.27](https://tex.z-dn.net/?f=N%282000%29%3D167.26532115499512956%5Capprox%20167.27)
Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.