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cricket20 [7]
3 years ago
10

WHOEVER ANSWERS THIS !ST IS GETTING ALL OF MY POINTS NNOT A JOKE PLEASEHELP ME FAST!

Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0

what number would you like answered


Tanzania [10]3 years ago
5 0

The prime is the number divided by 2 or 3 im pretty sure i do not really know sorry


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Write an addition sentence that helps you solve 15-9.​
Lemur [1.5K]

Answer:

I have 15 cookies and my brother ate 9 now I have 6 cookies.

8 0
2 years ago
12x+7&lt;−11 OR 5x−8&gt;40<br> solve for x
kipiarov [429]

Answer:

x < -1.5 U x > 9.6

Step-by-step explanation:

12x + 7 < -11

x < -1.5

5x - 8 > 40

5x > 48

x > 9.6

6 0
3 years ago
Read 2 more answers
What is 2/9 multiplied by 2 as a mixed number
olga_2 [115]

Answer:

4/9

Step-by-step explanation:

2/9 multiplied by 2 is 4/9 this can not be turned into a mixed number but can stay a fraction

5 0
3 years ago
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DUE TODAY!!!! I WILL MARK BRAINLIST
11Alexandr11 [23.1K]
Median: 3
mode: 3
range: 9
interquartile range: 2

the outliers are 9 and 5. there is a cluster between 2 and 3.
5 0
3 years ago
Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently
garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

\small \sum_{i = 1}^{k} L_i= 2\pi

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

 \small \sum_{i = 1}^{k} C_i.l = 2\pi

where C(i) is a constant coefficient obviously between 0 and 1.

\small \sum_{i = 1}^{k} C_i= 2\pi/l

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

\small L_{Exp} = \frac{2\pi}{k}

7 0
2 years ago
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