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Morgarella [4.7K]
3 years ago
13

I am doing Transforming Equations Containing only Variables : Algebra 1 :

Mathematics
2 answers:
Galina-37 [17]3 years ago
5 0
Rearrange: by= -ax+c
Cancel: by/b=(c-ax)/b
Answer: y= c-ax/b



fomenos3 years ago
3 0
Y=(c-ax) divided by b

The (c-ax) is divided as a whole over b. Thus reaching an answer for y. 
  
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How would I find the value of X in this equation
slava [35]
Sum of angles In all triangles are 180....line DAC is horizontal and therefore is 180 degrees ....so minus 180 degrees from 105 and you get 75 degrees....and since the sum of all angles in a triangle is 180...add 75 and 67 which would be 142 degrees ...then minus 142 from 180 degrees to get 38 degrees for x
4 0
3 years ago
Find the area of the parallelogram.<br> 3 yd<br> 9 yd
Firlakuza [10]
27 yd2 (b•h) it’s just like a rectangle
4 0
3 years ago
Read 2 more answers
What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?
11111nata11111 [884]

Answer:

R' = (-1,-0.5)

Step-by-step explanation:

See attachment for complete question.

From the attachment:

P = (-3,-3)

R = (1,2)

Dilation:

D_{(0.5,P)}

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

R = (1-(-3),2-(-3))

R = (1+3,2+3)

R = (4,5)

Next, apply dilation factor 0.5

R' = R * 0.5

R' = (4,5) * 0.5

R' = (4* 0.5,5* 0.5)

R' = (2,2.5)

Lastly, measure R' from the origin by adding the coordinates of P to R'

R' = (2+(-3),2.5+(-3))

R' = (2-3,2.5-3)

R' = (-1,-0.5)

6 0
3 years ago
So a computer is priced at the store for $380over a holiday weekend the store is having a 15% discount how much money would you
Rufina [12.5K]

Answer:

the answer is $57

Step-by-step explanation:

380 - 15% = 323. meaning $57 was saved.

8 0
3 years ago
The density of a American white oak tree is 752 kilograms per cubic meter. If the trunk of an American white oak tree has a circ
LuckyWell [14K]

Check the picture below.

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\ \cline{1-1} C=4.5 \end{cases}\implies 4.5=2\pi r\implies \cfrac{4.5}{2\pi }=r \\\\[-0.35em] ~\dotfill

\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} h=8\\ r=\frac{4.5}{2\pi } \end{cases}\implies V=\pi \left( \cfrac{4.5}{2\pi } \right)^2(8)\implies V=\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} \cdot \cfrac{20.25}{\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}\underset{\pi }{\begin{matrix} \pi^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }}(\stackrel{2}{\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}})

\bf V=\cfrac{40.5}{\pi }~cm^3~\hspace{9em} \stackrel{\textit{since density is }752kg~per~cm^3}{density\implies 752\left( \cfrac{40.5}{\pi } \right)}\qquad \approx ~~9694

8 0
3 years ago
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