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rjkz [21]
3 years ago
5

For her homework, Annie has added the picture of a fruit in a document. She wants to enhance it to give a cut-out look. Which fe

ature or menu option should she use
Computers and Technology
2 answers:
Kaylis [27]3 years ago
8 0

Answer:

Explanation:

We must follow several steps:

  1. We must click in the image
  2. Click Image Tools > Format
  3. Click the date under Crop
  4. We must resize the image, or Trim one side, Trim two adjacent sides, Trim the same fragment.
  5. Click the Crop button again if you finished

In addition, we can change the form of the image, we have a lot of options in crop to shape.

liubo4ka [24]3 years ago
3 0

Answer: A - smartart

Explanation:

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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Gnoma [55]

Answer:

public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

Explanation:

Using Java prograamming Language.

The Method (function) print_popcorn_time is defined to accept a single parameter of type int

Using if...else if ....else statements it prints the expected output given in the question

A complete java program calling the method is given below

public class num6 {

   public static void main(String[] args) {

       int bagOunces = 7;

       print_popcorn_time(bagOunces);

   }

   public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

}

3 0
3 years ago
Which of the four digital-to-analog conversion techniques (ASK, FSK, PSK or QAM) is the most susceptible to noise? Defend your a
grigory [225]

Answer:

ASK

Explanation:

The correct answer is ASK which denotes Amplitude Shift Keying. This is essentially a type of amplitude modulation which represents the binary data that comes varied forms right in the amplitude of a signal.

Now the reason why It is the most susceptible technique to noise is due to the fact that between frequency, phase & amplitude, amplitude is the one that is most susceptible to being affected by noise when compared to the other two.

3 0
3 years ago
Características que debe tener un módulo o kit tecnológico para aprender​
12345 [234]

Answer:

Multi herramientas

Explanation:

Un kit tecnologico debe contener todas las herramientas necesarias para el trabajo que lo necesites, por ejemplo destornillador magnetico con varias puntas, herramientas para desmontar y por supuesto tener buena claridad para trabajar y alcohol isoprofilico de al menos 90+ para limpiar electronicos.

5 0
2 years ago
What is responsible for what u see on a computer monitor?
zhuklara [117]
What is responsible or who is responsible?
3 0
3 years ago
Given public class Fishing { byte b1 = 4; int i1 = 123456; long L1 = (long) i1; //Line A short s2 = (short) i1; //Line B byte b2
Aleksandr [31]

Answer:

Line E.

Explanation:

The  given program is as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = b1 + 7;     //Line E

   }

In the above code Line E will not compile and give following compilation error:

error: incompatible types: possible lossy conversion from int to byte

This error is coming because in Java b1 + 7 will be interpreted as int variable expression. Therefore in order to make code of Line E work the expression should be type casted as byte.  

The correct code will be as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = (byte)(b1 + 7);     //Line E

   }

5 0
3 years ago
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