Answer:
b. to the end of the line
Explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
Python is a unique language compared to other languages such as Java and C++. In Python comments are started with the comment marker which is the hashtag (#) symbol and continues <u>to the end of the current line</u>. Once the line ends the next line is <u>NOT</u> automatically considered a comment unless another hashtag is placed.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
Answer:
do what the directions say and you should be able to figure out the answer if not contact me through brainly
Explanation:
The retina is the part pf the eye that is similar to the film of a camera. It is a thin layer of cells that is located at the back of the eyeball. This part contains photoreceptor cells which respond to light where the neural signals received undergoes complex processing by other neurons in the retina.