Let
rA--------> radius of the circle A
rB-------> radius of the circle B
LA------> <span>the length of the intercepted arc for circle A
</span>LB------> the length of the intercepted arc for circle B
we have that
rA/rB=2/3--------> rB/rA=3/2
LA=(3/4)<span>π
</span>
we know that
if <span>Both circle A and circle B have a central angle , the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the length of circle A to the length of circle B
</span>rA/rB=LA/LB--------> LB=LA*rB/rA-----> [(3/4)π*3/2]----> 9/8π
the answer is
the length of the intercepted arc for circle B is 9/8π
(x + 5)²z
(x + 5)(x+ 5)z
(x² + 5x + 5x + 25)z
(x² + 10x + 25)z
(x²)z + (10x)z + (25)z
x²z + 10xz + 25z
Let x = hats she knitted
Less than means to subtract and it’s an order switcher so it would be
2x - 6 = 78
First step: Add six to both sides -6 + 6 = 0 6 + 78 = 84
2x - 6 = 78
+ 6. +6
2x = 84
Second step: Divide the coefficient on both sides, two is the coefficient
2x/2 = x
2/84 = 42
Therefore, the answer is x= 42
The answer to this question is <span>B. (sqrt 2, 315 degrees). This polar coordinate is the only coordinate with its angle in quadrant 4 and a length of √1^2 + (-1)^2 = √2.</span>
