We have two right triangles and three different rectangles.
The formula of an area of a right triangle:
l₁, l₂ - legs
We have l₁ = 20cm and l₂ = 21cm. Substitute:
The formula of an area of a rectangle:
l - length
w - width
We have:
rectangle #1: l = 22cm, w = 29cm
rectangle #2: l = 22cm, w = 21cm
rectangle #3: l = 22cm, w = 20cm
The total Surface Area of the triangular prism:
Answer:
(4,5)
Step-by-step explanation:
The "feasible region" has vertices (0,0), (7,0), (5,4), and (4,5)
P = 5x + 6y
Plug in each vertices in P and find out which give maximum value
(0,0) => P= 5(0) + 6(0) = 0
(7,0) => P= 5(7) + 6(0) = 35
(5,4) => P= 5(5) + 6(4) = 49
(4,5) => P= 5(4) + 6(5) = 50
We got maximum P=50 for vertex (4,5)
So the coordinates of the point that has the maximum value is (4,5)
Step-by-step explanation:
(x10,y-2), reflection over y=1
3(2x+2)+x+5=-10
6x+6+x+5=-10
7x+11=-10
7x=-21
x=-3
To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.
Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.
Combining the three, we have the overall GCF = 3m2n
