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3 years ago

The ratio of width to length of a rectangle is 7:10.The width of the rectangle is 91 cm.

Mathematics

1 answer:

kvasek [131]3 years ago

6 0

Answer:

Length= 130 cm

For, Width= 91 cm

Step-by-step explanation:

Ratio of the width to the length of the rectangle = 7:10

Width of the rectangle= 91 cm

$\frac{Width}{Length} =\frac{7}{10}$

As, Width = 91 cm

$\frac{91}{Length} =\frac{7}{10}$

On, Cross multiplication the fraction:

$91*10=7*Length$

$7*Length=910$

Dividing by '7' both the sides:

$Length=\frac{910}{7}\\\\ Length=130cm$

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Solve by using elimtation

Wewaii [24]

Answer:

1. x = 5, y = 13/2

2. x = 15 , y = 24

Step-by-step explanation:

Solve the following system:

{8 y + 6 x = 82 | (equation 1)

{6 y + 9 x = 84 | (equation 2)

Swap equation 1 with equation 2:

{9 x + 6 y = 84 | (equation 1)

{6 x + 8 y = 82 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{9 x + 6 y = 84 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 1 by 3:

{3 x + 2 y = 28 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + 2 y = 13 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x + 0 y = 15 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Divide equation 1 by 3:

{x + 0 y = 5 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Collect results:

Answer: {x = 5, y = 13/2

_____________________________________

Solve the following system:

{8 y + 3 x = 237 | (equation 1)

{3 y + 5 x = 147 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 3 y = 147 | (equation 1)

{3 x + 8 y = 237 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = 147 | (equation 1)

{0 x + (31 y)/5 = 744/5 | (equation 2)

Multiply equation 2 by 5/31:

{5 x + 3 y = 147 | (equation 1)

{0 x + y = 24 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x + 0 y = 75 | (equation 1)

{0 x + y = 24 | (equation 2)

Divide equation 1 by 5:

{x + 0 y = 15 | (equation 1)

{0 x + y = 24 | (equation 2)

Collect results:

Answer: {x = 15 , y = 24

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2 years ago

What are the points of trisection of the segment with endpoints (0,0) and (27,27) ?

stiks02 [169]

Given:

Endpoints of a segment are (0,0) and (27,27).

To find:

The points of trisection of the segment.

Solution:

Points of trisection means 2 points between the segment which divide the segment in 3 equal parts.

First point divide the segment in 1:2 and second point divide the segment in 2:1.

Section formula: If a point divides a line segment in m:n, then

$Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Using section formula, the coordinates of first point are

$Point\ 1=\left(\dfrac{1(27)+2(0)}{1+2},\dfrac{1(27)+2(0)}{1+2}\right)$

$Point\ 1=\left(\dfrac{27}{3},\dfrac{27}{3}\right)$

$Point\ 1=\left(9,9\right)$

Using section formula, the coordinates of first point are

$Point\ 2=\left(\dfrac{2(27)+1(0)}{2+1},\dfrac{2(27)+1(0)}{2+1}\right)$

$Point\ 2=\left(\dfrac{54}{3},\dfrac{54}{3}\right)$

$Point\ 2=\left(18,18\right)$

Therefore, the points of trisection of the segment are (9,9) and (18,18).

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Answer:

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amid [387]

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2 years ago

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wolverine [178]

Answer:

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Step-by-step explanation:

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