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STatiana [176]
3 years ago
14

Please please please help!!!!!!!

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

  x = 12

Step-by-step explanation:

The length of the midsegment is the average of the lengths of the other two.

  5x -20 = ((4x +2) +(2x +6))/2

  5x -20 = 3x +4 . . . . . . . . . . . . simplify

  2x = 24 . . . . . . . . . . . . . . . . . . add 20-3x

  x = 12 . . . . . . . . . . . . . . . . . . . . divide by 2

_____

<em>Check</em>

The three segment lengths are ...

  top: 2·12 +6 = 30

  midsegment: 5·12 -20 = 40

  bottom: 4·12 +2 = 50

Indeed, 40 is the average of 30 and 50.

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In right triangle ABC, if angle A is 90 degrees, angle C is 34 degrees, and AC is 71.4, find BC.
AURORKA [14]

We are given that

In right triangle ABC, if angle A is 90 degrees, angle C is 34 degrees, and AC is 71.4, find BC.

Solution

We will first draw a diagram to illustrate the information

Above we want to find x

The method to use is SOHCAH

From the right angle triangle above we have above, we have the adjacent side and we want to find the hypotenus, so we use cosine

i.e

\cos 34=\frac{71.4}{x}

We need to solve for x here

\begin{gathered} x=\frac{71.4}{\cos 34} \\ x=86.12396152 \\ x=86.1\text{ (to the nearest tenth)} \end{gathered}

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1 year ago
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Sidana [21]

Answer:

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Step-by-step explanation:

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3 years ago
Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born
NikAS [45]

Answer:

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Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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p = \frac{31}{365} = 0.0849

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This means that n = 20

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

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Answer:

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