Sin θ=sqrt(1-<span>cos^2 θ)
</span>sin θ=sqrt[1-(5/13)^2]
sin θ=sqrt[1-(5)^2/(13)^2]
sin θ=sqrt[1-25/169]
sin θ=sqrt[(169-25)/169]
sin θ=sqrt(144/169)
sin θ=sqrt(144)/sqrt(169)
sin θ=12/13
Answer: Second option 12/13
2x-3(0)=12
2x=12
x=6
(6,0)
2(0)-3y=12
-3y=12
y=-4
(0,-4)
2x-3(2)=12
2x-6=12
2x=18
x=9
(9,2)
ANSWERS: (6,0) (0,-4) (9,2)
Answer:
-2z-2
Step-by-step explanation:
5z-8-4z-3z+6
5z-4z-3z-8+6
-2z-2
<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,

As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then 
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.
Answer:
15.4
Step-by-step explanation:
rounded its 15