The solutions of the equations of the situation can be:
z = 1 , y = 5, x = 4
z= 2 , y = 3, x = 5
z=3 , y = 1, x = 6
z = 0 , y = 7, x =3
The question can be expressed as a equation
6 x + 8 y + 10 z = 84
also, x + y + z = 10
⇒ x = 10- y - z
Putting it in first equation,
6(10 - y - z ) +8y + 10z = 84
⇒ 60 +2y + 4z = 84
⇒2(y + 2z ) = 14
⇒ y + 2z = 7
Now putting
z = 1 , we get y = 5,
z= 2 , y = 3
z=3 , y = 1
z = 0 , y = 7
So, only 4 possible solutions.
Therefore, there can only be 4 possible solutions for the equations.
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Volume = length x width x height.
if the width has to be a whole number no more than 5 then the only options for the width is 1, 2, 3, 4, or 5.
V=5x1x2
V=10
V=5x2x2
V=20
V=5x3x2
V=30
V=5x4x2
V=40
V=5x5x2
V=50
the possible volumes are as follows: 10, 20, 30, 40, and 50.
make sure in your answer that you label your volumes so you write ft^3 after every volume answer.
Answer:
b = 58
Step-by-step explanation:
Complementary angles add to 90 degrees.
a+b = 90
32+b = 90
Subtract 32 from each side
32+b-32 = 90-32
b = 58
Answer:
A simplified method for dividing a polynomial by another polynomial of the first degree is synthetic division.
Answer:
(D) There are probably more blue marbles than red marbles in the bag.
Step-by-step explanation:
There are a total of 100 marbles in the bag.
In the experiment of 50 trials, Sam had the following outcome:
Blue=35
Red=15
Relative Frequency of Blue Marbles =35/50=0.7
Relative Frequency of Red Marbles =15/50=0.3
Since the relative frequency of blue marbles is greater than the relative frequency of red marbles, <u>there are probably more blue marbles than red marbles in the bag.</u>
The correct option is D.
