What is the equation of a circle whose center is at the origin and whose radius is 16

Mathematics

2 answers:

ankoles [38]3 years ago

7 0

Answer: The equation of the circle is $x^2+y^2=256.$

Step-by-step explanation: We are given to find the equation of a circle whose center is at the origin and whose radius is 16 units.

The standard equation of a circle with center at (g, h) and radius 'r' units is given by

$(x-g)^2+(y-h)^2=r^2.$

According to the given information,

Center is at the origin (0, 0), so, (g, h) = (0, 0),

and radius, r = 16.

Therefore, the equation of the circle is given by

$(x-0)^2+(y-0)^2=16^2\\\\\Rightarrow x^2+y^2=256.$

Thus, the required equation of the circle is $x^2+y^2=256.$

earnstyle [38]3 years ago

3 0

So this equation will be

x^2 +y^2 = 16^2

hope this will help you

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