The Answer Is 7.5
Tangent and 8 makes a right triangle, which is great because you could find the diameter and divide it by 2 to find the radius.
64+d^2=289
d^2=225
d=15
15/2=7.5
The answer is -93, here is the work :)
We first start by finding the actual coordinates of the pre - image's point S.
Assuming the x and y axis count by 1s, as there is no labels, we can conclude that:
The point's x coordiate is 4 to the left from the origin, or -4.
The point's y coordinate is 4 up from the origin, or 4.
So, the coordinates of Point S is (-4, 4).
Next, we apply the translation rule for a 90 degree counterclockwise rotation to the point's coordinates. The rule is (x, y) --> (-y, x). Using this rule on our coordinates, we get:
(-4, 4) --> (-4, -4)
So, the new coordinates of point S prime after a 90 degree counterclockwise rotation are (-4, -4).
Given :
- A = {x: 2x² + 3x - 2 = 0 }
- B = {x : x² + 3x - 4 = 0 }
To find :
Solution :-
<u>The </u><u>first </u><u>set </u><u>is </u><u>,</u>
- A ={x : 2x² + 3x - 2 = 0}
<u>Solving</u><u> </u><u>the </u><u>Quadratic</u><u> equation</u><u> </u><u>,</u>
- 2x² + 3x - 2 = 0
- 2x² + 4x - x - 2 = 0
- 2x( x + 2) -1( x + 2 ) = 0
- (2x -1) ( x + 2) = 0
- x = 0.5 , -2
<u>Hence</u><u> </u><u>,</u>
<u>The </u><u>second</u><u> </u><u>set </u><u>is </u><u>,</u>
- B ={ x :x² + 3x - 4 = 0 }
<u>Solving</u><u> the</u><u> Quadratic</u><u> equation</u><u> </u><u>,</u>
- x² + 3x - 4 = 0
- x² + 4x - x - 4 = 0
- x( x + 4)-1 ( x +4) = 0
- (x + 4) ( x -1) = 0
- x = 1 , -4
<u>Hence</u><u> </u><u>,</u>
<u>Now </u><u>,</u>
- A U B = { 0.5 , 1 , 4 , -2}
- A Π B = {∅ }
Since AΠ B is a null set , hence ,
The answer two your problem is no remainder again because 46 divided by 2 equals 23