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madreJ [45]
3 years ago
10

A coordinate grid is placed over a college Station map. Tiger Stadium is located at (-3,2)

Mathematics
1 answer:
Olin [163]3 years ago
6 0

Answer:

4.61\ units

Step-by-step explanation:

<em><u>The complete question is</u></em>

A coordinate grid is placed over a  College Station map.  Tiger Stadium is         located at (-3, 2) and Kyle Field is located at (4, 8).  If a shuttle bus stop is         at the midpoint between Tiger Field  and Kyle Field, which is the closest to         the distance in coordinate units from  Tiger Field to the shuttle bus stop?

<u><em>Options</em></u>

4.61 units

6.52 units  

9.22 units  

21.25 units

step 1

Find the midpoint between Tiger Field  and Kyle Field ( shuttle bus stop)

we know that

The formula to calculate the midpoint between two points is equal to

M=(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have the points

(-3, 2) and (4, 8)

substitute in the formula

M=(\frac{-3+4}{2},\frac{2+8}{2})

M=(0.5,5)

step 2

Find the distance from  Tiger Field to the shuttle bus stop

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

(-3,2) and (0.5,5)

substitute in the formula

d=\sqrt{(5-2)^{2}+(0.5+3)^{2}}

d=\sqrt{(3)^{2}+(3.5)^{2}}

d=\sqrt{21.25}\ units

d=4.61\ units

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Let d represent the distance of the destination from the starting point.

After 45 min, Henry has already driven d-68 miles.  After 71 min., he has already driven d-51.5 miles.

So we have 2 points on a straight line:

(45,d-68) and (71,d-51.5).  Let's find the slope of the line thru these 2 points:

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slope of line = m = ----------------------- = ------------------
                                     71 - 45                   26 min

Thus, the slope, m, is   m = 0.635 miles/min

The distance to his destination would be d - (0.635 miles/min)(79 min), or 

d - 50.135 miles.  We don't know how far his destination is from his starting point, so represent that by "d."

After 45 minutes:  Henry has d - 68 miles to go;

After 71 minutes, he has        d - 51.5 miles to go; and

After 79 minutes, he has         d -  x miles to go.  We need to find x.

Actually, much of this is unnecessary.  Assuming that Henry's speed is 0.635 miles/ min, and knowing that there are 8 minutes between 71 and 79 minutes, we can figure that the distance traveled during those 8 minutes is

(0.635 miles/min)(8 min) = 5.08 miles.  Subtracting thix from 51.5 miles, we conclude that after 79 minutes, Henry has (51.5-5.08), or 46.42, miles left before he reaches his destination.




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Step-by-step explanation:

gcf means the the greatest factor that works for both terms

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    let's first find the gcf for the coefficient

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3)

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by understanding 3) hopefully you can understand 4)

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I'm not sure but I think it is this

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