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jok3333 [9.3K]
3 years ago
15

HELP THANKS LOVE YOU

Mathematics
2 answers:
galben [10]3 years ago
5 0

Answer:

length of line segment PQ is 5 units

Step-by-step explanation:

Tangent secant theorem

MN² = QN x PN

6² = 4(x+4)

36 = 4x + 16    Plug in values into exponents

20 = 4x     Subtract 16 from both sides

x = 5    Divide by 4 to isolate the variable

MrRa [10]3 years ago
4 0

Answer:

5 units

Step-by-step explanation:

The product of the length of the secant segment and its external part equals the square of the length of the tangent segment.

4 * (4+x) = 6^2

Distribute

16 +4x = 36

Subtract 16 from each side

16-16+4x = 36-16

4x= 20

Divide each side by 4

4x/4 = 20/4

x=5

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The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

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Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

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c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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