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finlep [7]
3 years ago
9

Factor -4 out of -8d+20

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

-4(2d-5)

Step-by-step explanation:

-8d+20

-4(2d-5)

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A=19,900×(1+0.03)^(10)
A=26,744
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Need helpp quickkk 14 points
Aneli [31]

Step-by-step explanation:

it is also the same process

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edna was walking the oregon trail in one day she walked 27 miles. it took her 9 hours what was her average speed
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3 years ago
The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =
gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

f_x(x)  = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0

Thus, the expected  total claim amount \mu =  1000

The variance of the total claim amount \sigma ^2  = 1000^2

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})

P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})

P(X>1100n) = P(Z> \dfrac{10*100}{1000})

P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345

\mathbf{P(X>1100n) = 0.158655}

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

4 0
3 years ago
Write a linear equation representing the information shown in the table.
Law Incorporation [45]

Answer:

A

Step-by-step explanation:

This is how I write

y=kx+m

but I have seen some write it like this:

y=mx+b

Well both of them are the same thing, I'll use the first one because I'm more comfortable with it.

y=kx+m

To find out what k

k =  \frac{y2 - y1}{x2 - x1}

So you first need to choose two points.

I'll go for (0,-5) and (2,0)

k =  \frac{0 - 5}{2 - 0}

k = \frac{ - 5}{2}

Now you could insert k into the equation and it will look like this.

y =  \frac{ - 5}{2}x + m

To find out what m is just pick one point and insert it into the equation. So if I pick (0,-5). 0=X therefore it should be replaced by x and -5=y therefore it should also be replaced by y.

- 5 =  \frac{ - 5}{2} \times 0 + m

m=-5

Try it with another point to see if you get the same answer. this time I'll pick (-6,10)

10=  \frac{ - 5}{2} \times( - 6)+ m

m= -5

The equation will be y=-5/2x-5)

8 0
3 years ago
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