Answer:
tom = 166, ben = 581
Step-by-step explanation:
2 + 7 = 9
747 ÷ 9 = 83
therefore 1 part = 83
83 x 2 = 166
83 x 7 = 581
tom has 2 parts so he has 166
ben has 7 parts so he has 581
Answer:
y ≥ x^2 - 1
Step-by-step explanation:
First, we can see that the shaded region is above what seems to be a parabola, and we also can see that the lines of the parabola are solid lines (which means that the points on the curve itself are solutions, so the symbol ≥ is used)
Then:
y ≥ a*x^2 + b*x + c
where a*x^2 + b*x + c is the general quadratic equation.
Now let's find the equation for the parabola:
f(x) = a*x^2 + b*x + c
We also can see that the vertex of the parabola is at the point (0, -1)
This means that:
f(0) = -1 = a*0^2 + b*0 + c
= -1 = c
then we have that c = -1
Then:
f(x) = a*x^2 + b*x - 1
Now we can look at the graph again, to see that the zeros of the parabola are at +1 and -1
Which means that:
f(1) = 0 = a*1^2 + b*1 - 1 = a + b - 1
f(-1) = 0 = a*(-1)^2 + b*(-1) - 1 = a - b - 1
Then we got two equations:
a + b - 1 = 0
a - b - 1 = 0
from this we can conclude that b must be zero.
Then:
b = 0
and these equations become:
a - 1 = 0
a - 1 = 0
solving for a, we get:
a = 1
Then the quadratic equation is:
f(x) = 1*x^2 + 0*x - 1
f(x) = x^2 - 1
And the inequality is:
y ≥ x^2 - 1
Minus 16x both sides and add 28 to both sides
x^2-16x+28=0
factor
hmm, what 2 numbers multiply to 28 and add to -16
hmm
1 and 28? nope
2 and 14? yep
since middle term is negative and last tem is positive, both of the factors are negative
(x-14)(x-2)=0
set each to zero
x-14=0
x=14
x-2=0
x=2
x=2 and 14
The number given in the question is in decimal form. It has to be first changed to fraction and then only can it be changed to a mixed fraction. The calculations have to be done correctly and then the problem is very straight forward.Now let us concentrate on the problem in hand.
Then
6.54 = 654/100
= 327/50
= 6 27/50
From the above deduction we can definitely conclude that the mixed number for 6.54 is 5 27/50. I hope this simple procedure will help you to attempt such type of problems in future without requiring any additional help.
Answer:
8
Step-by-step explanation:
not sure if this is what ur looking for sorry
