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In-s [12.5K]
3 years ago
11

Which expression defines the arithmetic series 1+3+5+... for seven terms

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0
1+3+5+7+9+11+13+15+17+19 is the answer. Hopefully this helped!! :)
nydimaria [60]3 years ago
3 0

Answer: The expression for arithmetic series for seven terms is given by

\sum_{n=1}^{n=7}(2n-1)

Step-by-step explanation:

Since we have given that

1+3+5+..................

Here, a = 1

d= common difference = a₂-a₁=3-1=2

n = 7

We need to write the arithmetic series for seven terms:

\sum_{n=1}^{n=7}(2n-1)

Hence, the expression for arithmetic series for seven terms is given by

\sum_{n=1}^{n=7}(2n-1)

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point q is located in ( -4 , 6) point r is located in ( 8,6) . what is the distance from pint q to point r
Hoochie [10]

Answer: 12

Step-by-step explanation: It’s on the same y axis and -4 to 8 is going to the right on a graph.

5 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Which transformation changes triangle ABD to triangle A'B'C'?
VARVARA [1.3K]

Answer:

Mostly answer is A but am confused btwn A and D I'll let you know when I'm sure

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Answer:

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7 times the sum of a number and 3
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Step-by-step explanation:

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