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Viktor [21]
4 years ago
10

Imagine a solution of two liquids in which the molecules interact less favorably than they do in the individual liquids. Will th

is solution deviate positively from, deviate negatively from, or ideally follow Raoult's law
Chemistry
1 answer:
kupik [55]4 years ago
8 0

Answer : The correct option is, solution deviate positively from.

Explanation:

According to the Rouault's law, there are two types of deviation which are negative deviation and positive deviation.

In negative deviation, the A-A interactions and B-B interactions are weaker than the A-B interactions that means A-B interactions are more due hydrogen bonding.

For example : chloroform & acetone form a non-ideal solution. The volume of solution will always be more.

In positive deviation, the A-A interactions and B-B interactions are stronger than the A-B interactions.

For example : acetone & benzene form a non-ideal solution. The volume of solution will always be less.

As per question, the interaction between individual liquids are stronger than the solution of two liquid's interactions. That means, the solution deviate positively from.

Hence, the correct option is, solution deviate positively from.

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Specific gravity of mercury is 13.56 and it is an unit-less quantity.

Explanation:

Mass of the mercury = m = 607.0 lb = 275330.344 g

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Density of the mercury = d=\frac{m}{v}=\frac{275330.344  g}{20,303.18 mL}

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Specific gravity of substance = Density of substance ÷ Density of water

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Specific gravity of mercury :

S.G=\frac{13.56 g/mL}{1 g/mL}=13.56 (unit-less quantity)

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