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diamong [38]
3 years ago
12

Explain a polar molecules and give examples​

Chemistry
1 answer:
ivanzaharov [21]3 years ago
8 0
Ethanol is polar because the oxygen atoms attract electrons because of their higher electronegativity than other atoms in the molecule. Thus the -OH group in ethanol has a slight negative charge. Ammonia (NH3) is polar. Sulfur dioxide (SO2) is polar.
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(-3,5); m= 2/3 plzzzzz help
AveGali [126]

Setting up the equation, you get

5=\frac{2}{3} *(-3)+b

b=7

Therefore, the equation is y=\frac{2}{3} x+7


6 0
3 years ago
Read 2 more answers
PLZ HELP ASAP!!!
melomori [17]
Sandy soil because the sand will erode faster then the clay will causeing the well to cave in
6 0
3 years ago
How many grams of Ag2S2O3 form
Art [367]

Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgBr: 2 moles
  • Na₂S₂O₃: 1 mole
  • Ag₂S₂O₃: 1 mole
  • NaBr: 2 moles

The molar mass of the compounds is:

  • AgBr: 187.77 g/mole
  • Na₂S₂O₃: 158 g/mole
  • Ag₂S₂O₃: 327.74 g/mole
  • NaBr: 102.9 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • AgBr: 2 moles ×187.77 g/mole= 375.54 grams
  • Na₂S₂O₃: 1 mole ×158 g/mole= 158 grams
  • Ag₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 grams
  • NaBr: 2 moles ×102.9 g/mole= 205.8 grams

<h3>Mass of Ag₂S₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?

mass of Ag_{2} S_{2} O_{3} =\frac{125 grams of AgBrx327.74 grams of Ag_{2} S_{2} O_{3}}{375.54 grams of AgBr}

<u><em>mass of Ag₂S₂O₃= 109.09 grams</em></u>

Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

4 0
2 years ago
After 11.5 days, 12.5% of a sample of radon-222 that originally weighed 42g remains. What is the half-life of this isotope?
Bond [772]
Half-life is defined as the amount of time it takes a given quantity to decrease to half of its initial value.  The equation to describe the decay is
Nt=N0(1/2) ^{t/t(1/2)}  where N0 is the initial quantity, Nt is the remaining quantity after time t, t1/2 is the half-time.  So work out the equation, t1/2 = t (-ln2)/ln(Nt/N0) = 11.5*(-ln2)/ln(12.5/100) = 3.83 days
5 0
3 years ago
What mass of h2o is formed when h2 reacts with 384 grams of o2?
Tasya [4]
Answer is: mass of water is 432 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(O₂) = 384 g.
M(O₂) = 2 · 16 g/mol = 32 g/mol, molar mass.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 384 g ÷ 32 g/mol.
n(O₂) = 12 mol, amount of substance.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 12 mol · 2 = 24 mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 24 mol · 18 g/mol.
m(H₂O) = 432 g.
8 0
3 years ago
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