Question

If x = √3 − √2 , find the value of ( −1/x)root 2

Answer 1

hello

$\dfrac{-1}{x}\sqrt{2}=\dfrac{-\sqrt{2}}{\sqrt{3}-\sqrt{2}}=\dfrac{-\sqrt{2}(\sqrt{3}+\sqrt{2})}{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})}\\\\=\dfrac{-\sqrt{2}(\sqrt{3}+\sqrt{2})}{3-2}\\\\=-\sqrt{6}-2$

hope this helps