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Keith_Richards [23]

2 years ago

5

Solve the word problem. the area of a given triangle is 20cm^2 and it's base is 5cm. what is the height of the triangle?

1 answer:

Kitty [74]2 years ago

8 0

Hello:

<span>area : a = (b×h)/2
20 = (5×h)/2
h = (20×2)/5 = 8 m² </span>

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Help with this question!

zheka24 [161]

Since AS is a height issued from A and the perpendicular bisector of [MP] at the same time (given), so the triangle AMP is an isosceles triangle of vertex A. Then, AM=AP
MS=SP ( AS bisects MP as stated in the given )
AS is a common side between triangles ASM and ASP
Therefore, triangles ASM and ASP are congruent (SSS)

7 0

3 years ago

Find the measure of the largest angle in ABC if a = 12, b = 8 and c = 13.

Papessa [141]

Answer:

$C=78.28^{\circ \:}$

Step-by-step explanation:

We are given a triangle

whose sides are

a=12

b=8

c=13

Since, c is largest among them

So, angle C must be largest angle

we can find angle C

we can use law of cosine formula

$cos(C)=\frac{a^2+b^2-c^2}{2ab}$

now, we can plug values

$cos(C)=\frac{12^2+8^2-13^2}{2\times 12\times 8}$

$cos(C)=\frac{13}{64}$

now, we can find angle

we get

$C=78.28^{\circ \:}$

5 0

2 years ago

A computer store bought a coat of $10 and sold if for $13 find the percent increase

lubasha [3.4K]

Answer:

30% increase

Step-by-step explanation:

30 is 30 percent of 100 so the answer is 30 percent increase

3 0

3 years ago

What is 10n+2=7n+14

Orlov [11]

Answer:

n = 4

Step-by-step explanation:

Given

10n + 2 = 7n + 14

Collect terms in n on the left side and numbers on the right side

Subtract 7n from both sides

3n + 2 = 14 ( subtract 2 from both sides )

3n = 12 ( divide both sides by 3 )

n = 4

4 0

3 years ago

Read 2 more answers

Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...

Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

$\displaystle -3x -1, \, 4x +4, \, 11x + 9 \dots$

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

$\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}$

Find the common difference by subtracting the first term from the second:

$d = (4x+4) - (-3x - 1)$

Distribute:

$d = (4x + 4) + (3x + 1)$

Combine like terms. Hence:

$d = 7x + 5$

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

$\displaystyle x_n = a + d(n-1)$

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

$\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)$

To find the 13th term, let <em>n</em> = 13. Hence:

$\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)$

Simplify:

$\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}$

The 13th term is 81<em>x</em> + 59.

3 0

3 years ago