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olga_2 [115]
3 years ago
15

5. Consider the line segment in the graph below. Part A: Draw a line segment parallel to AB passing through (-4,-1), that has th

e same length of AB. Name the line segment MY. Part B: Draw a line segment perpendicular to AB passing through (-3, 4) and intersecting both AB and MY. Name the line segment QU​

Mathematics
1 answer:
podryga [215]3 years ago
5 0

Answer:

See attached

Step-by-step explanation:

Both of the lines are drawn on the attached

A. .........................

Since lines AB and MY are parallel, and one of the points of parallel line is (-4, -1) the other point is going to have same difference of x and y-coordinates

  • A(-3, 2) → M (-4, -1) ⇒ B(2, 4) → Y(1, 1)

Connecting this two points, we get a parallel line to AB

<em>This is a blue line segment on the graph</em>

B. .........................

Perpendicular lines have slopes of negative reciprocal

Considering this and one of the points of a perpendicular line of (-3, 4)

we can calculate the other point.

  • Slope of AB = (4-2)/(2 +3) = 2/5
  • So slope of the lime QU = -5/2

The other point will have coordinates:

  • -3 + 2 = -1 , here 2 is the denominator of the slope

and

  • 4 -5 = -1, here -5 is the numerator of the slope

So the line segment is QU with coordinates of (-3, 4) and (-1, -1)

<em>This is red line segment on the graph</em>

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If they plan to start the test before lunch, then they should start at 10:10
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Calculate the size of a and b respectively in the diagram below​
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Answer:

a = 85°, b = 95°

Step-by-step explanation:

a = 180°-60°-35° (Sum of angles in a triangle)

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3 years ago
A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




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3 years ago
3/11 as a percentage
lina2011 [118]
<span>27.27%

I hope helped
Please left thanks
</span>
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3 years ago
What is 96.777778 rounded?
EleoNora [17]

Answer:

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