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3 years ago

Solve the linear equation. X + 5 = -2

Mathematics

2 answers:

Dafna11 [192]3 years ago

8 0

The answer is -7 .......

Vladimir79 [104]3 years ago

7 0

Answer:

$x=-7$

Step-by-step explanation:

So we have the equation:

$x+5=-2$

To solve, subtract 5 from both sides. This is the subtraction property of equality:

$(x+5)-5=(-2)-5$

The left side cancels:

$x=(-2)-5$

Subtract on the right.

$x=-7$

So, our answer is -7.

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Schach [20]

Answer: It is proportional because 195/3 equals 65 and 325/5 equals 65 as well, so it is proportional.

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr

Kobotan [32]

Answer:

% change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

$T = 2.5 x + 0.5 x^{2}$

We will approximate this distance using the relation

$f (x + dx) = f (x)+ f' (x)dx$

dx = 26 - 25 = 1

T' = 2.5 + x

Therefore

$f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x$

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× $25^{2}$ + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × $25^{2}$

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

% change in stopping distance = $\frac{27.5}{375}$ × 100

% change in stopping distance = 7.34 %

6 0

3 years ago

What is the equation?

elena-s [515]

Answer:

cost = 1.35n

$33.75 for 25 songs

Step-by-step explanation:

Based on the numbers given, the cost is proportional to the number of songs downloaded. The constant of proportionality is the cost of one song: 1.35.

cost = 1.35n

For 25 songs, ...

cost = 1.35·25 = 33.75 . . . . dollars

The equation is ...

cost = 1.35n

5 0

3 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$