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Fiesta28 [93]
3 years ago
7

Jenny spent 35 minutes doing research on the internet.she finished at 7:10 p.m. at what time did jenny start her research

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0
Jenny started her research at 6:45 PM.
jeyben [28]3 years ago
4 0
6:35pm, because 35 minutes before 7:10 pm is 6:35pm :)
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In your notebook, set up the following subtraction in a vertical format and select the correct answer. Find 2p 2 3p - 4 less - 2
Elena L [17]

The equation in the reduced form of the equation is \rm 4p^ 2 + 6p - 8.

Given that,

Equation; \rm  2p^ 2 + 3p - 4\  by\  -2p ^2 - 3p +4

We have to reduce the equation.

According to the question,

To reduce the equation means we need to subtract one equation from the other.

To determine the reduced form of the equation following all the steps given below.

Equation; \rm  2p^ 2 + 3p - 4\  by\  -2p ^2 - 3p +4

Subtraction equation 1 from equation 2,

\rm  = \rm  2p^ 2 + 3p - 4\  -(-2p ^2 - 3p + 4)\\\\=  2p^ 2 + 3p - 4\  -(-2p ^2 -3p +4)\\\\ = 2p^ 2 + 3p - 4+2p^ 2 + 3p - 4 \\\\ = 4p^ 2 + 6p - 8

Hence, The equation in the reduced form of the equation is \rm 4p^ 2 + 6p - 8.

For more details refer to the link given below.

brainly.com/question/1807316

3 0
2 years ago
A student was given an assignment to determine the percentage of students that brought a bag lunch to school. The student chose
Tju [1.3M]

Answer:

Step-by-step explanation:

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8 0
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pogonyaev

Answer: 8y4+25y3+60y2+10y+7

Step-by-step explanation:

(y2+3y+7)(8y2+y+1)

=(y2+3y+7)(8y2+y+1)

=(y2)(8y2)+(y2)(y)+(y2)(1)+(3y)(8y2)+(3y)(y)+(3y)(1)+(7)(8y2)+(7)(y)+(7)(1)

=8y4+y3+y2+24y3+3y2+3y+56y2+7y+7

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3 years ago
Domain of the function of a graph with coordinates (-3,-2)
olga2289 [7]

Answer:

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Step-by-step explanation:

Given that coordinate of a graph is (-3, -2)

We have to find out the domain.

We know that if A and B are two sets, a mapping from A to B is the subset of cartesian product AxB.

Domain is the set of values of A which have images in B.

Use the above definition.

We have A = {-3,...} and B = {-2,....}

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