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vladimir1956 [14]
2 years ago
5

To turn a decimal into a percent you move the decimal 2 spaces to which direction.

Mathematics
2 answers:
Ne4ueva [31]2 years ago
5 0

Answer:

Right

Step-by-step explanation:

You move the decimal to the right to make the decimal a whole number :)

Example below:

0.25

Move 2 places to the right

25%

Have a great day!!

Please rate and mark brainiest!!

zimovet [89]2 years ago
4 0

Answer: You move the decimal point two spaces to the right.

Step-by-step explanation:

Multiply by 100.

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What is 3.2Kg given to nearest 100g
vova2212 [387]
3.2x1000=3200
And that's your answer: 3200

Hope this helps :)
5 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes if any for f(x)=x/x-5
Gelneren [198K]

Answer:

Horizontal Asymptote: x = 0

Vertical Asymptote: x = 5

Step-by-step explanation:

The function is given as  f(x)=\frac{x}{x-5}

<em>Horizontal asymptotes are found by equating numerator to 0 and solving for x</em>

<em>Vertical asymptotes are found by equating denominator to 0 and solving for x</em>

<em />

<u>Horizontal Asymptote:</u>

x = 0

<u>Vertical Asymptote:</u>

x - 5 = 0

x = 5

5 0
3 years ago
5+8=6+7 true or false​
Romashka-Z-Leto [24]

Answer: True becuase  5+8 equals 13 and 6+7 also equal 13 so that means that they are equal to each other.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
4x?=298 show your work
mote1985 [20]
Divide 298 by 4 then you should get your answer
5 0
3 years ago
Read 2 more answers
How do you find absolute extrema for a function?<br> f(x)= (8+x)/(8-x); Interval of [4,6]
Mkey [24]
\bf f(x)=\cfrac{8+x}{8-x}\implies \cfrac{dy}{dx}=\stackrel{quotient~rule}{\cfrac{1(8-x)-(8+x)(-1)}{(8-x)^2}}\implies \cfrac{dy}{dx}=\cfrac{16}{(8-x)^2}

now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.

so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.

therefore, we settle for the endpoints, 4 and 6,

f(4) =3    and      f(6) = 7

doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.
3 0
3 years ago
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