![\bf \stackrel{height}{h(t)}=-16t^2+32t+48\implies \stackrel{48~ft}{~~\begin{matrix} 48 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=-16t^2+32t~~\begin{matrix} +48 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} \\\\\\ 0=-16t^2+32t\implies 16t^2-32t=0\implies 16t(t-2)=0\implies t= \begin{cases} 0\\ 2 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bheight%7D%7Bh%28t%29%7D%3D-16t%5E2%2B32t%2B48%5Cimplies%20%5Cstackrel%7B48~ft%7D%7B~~%5Cbegin%7Bmatrix%7D%2048%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%3D-16t%5E2%2B32t~~%5Cbegin%7Bmatrix%7D%20%2B48%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D%20%5C%5C%5C%5C%5C%5C%200%3D-16t%5E2%2B32t%5Cimplies%2016t%5E2-32t%3D0%5Cimplies%2016t%28t-2%29%3D0%5Cimplies%20t%3D%20%5Cbegin%7Bcases%7D%200%5C%5C%202%20%5Cend%7Bcases%7D)
t = 0 seconds, when the ball first took off, and t = 2, 2 seconds later.
Answer:
The cube root of 216 is 6
Answer:
5 and 0 between 250 and 300
Since a parabola is a function that is at the same height at two point except one that is in the middle. so the middle value is 4 and would be the max height.