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pashok25 [27]
3 years ago
13

Three angles of a triangle are cut off and lined up on the line below.   A straight line. 2 lines form a V and come out of the l

ine. The middle angle formed is 90 degrees, and the right angle is 45 degrees. Which statements describe the relationship of the angles in the triangle? Check all that apply. The sum of the three angles is 90°. The sum of the angles in the triangle is 180°. The three angles are adjacent and form a straight angle. The third angle is 45°. There is a pair of congruent angles.
Mathematics
2 answers:
erik [133]3 years ago
5 0

Answer:

2 3 4 5

Step-by-step explanation:

Gwar [14]3 years ago
4 0

Answer:

last 4

Step-by-step explanation:

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6.) Convert the following linear equation into slope-intercept form.<br><br> 4x + 3y = 9
viktelen [127]

Answer:

y=\frac{-4}{3} +9

Step-by-step explanation:

Slope-intercept form is y-mx+b. To find slope-intercept form solve for y.

First, subtract 4x from both sides,

3y=-4x+9

Then, divide both sides by 3,

y=-4/3x+3

5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST! SUPER CONFUSED!!!
kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

5 0
4 years ago
Michael is 25 years younger than his father. The sum of their ages is 53. What is Michael’s age
ki77a [65]

Answer: 14

Step-by-step explanation:

⇒ Michael's age = x −25

⇒ x − 25 + x = 53

⇒ 2x = 53 + 25

⇒ 2x =78

⇒ x =39

Hence, Michael's age

<h2>= x − 25 = 39 − 25 = 14 </h2>

* Hopefully this helps:) Mark me the brainliest:)!!!

<em>~234483279c20~</em>

5 0
3 years ago
A line segment has endpoints (4 7) and (1 11). what is the length of the segment
Colt1911 [192]
You need to add the number of blocks or lines are betweenhem.
7 0
4 years ago
A voice grade modem has a maximum data rate of 14,400 bps. What would be the maximum data rate of that modem if the number of po
max2010maxim [7]

The maximum data rate of that modem is doubled if the number of points in its constellation were doubled

According to statement

Modem has a data rate is 14,400 bps

we know that the data rate can be calculated by T=A/S

If a is Doubled then the data rate is also doubled.

Because A is directly proportional to the T and S is inversely proportional to T.

So, The maximum data rate of that modem is doubled if the number of points in its constellation were doubled

Learn more about DATA RATE here brainly.com/question/25109150

#SPJ4

7 0
2 years ago
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