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Nady [450]
3 years ago
6

What is the answer to 10 - s when s = -3

Mathematics
2 answers:
Alex Ar [27]3 years ago
7 0
When you replace s with -3, it is 10--3. One is negative and one is positive, so you make -- ( subtract negative) into a +( plus add). So 10+3=13
Stells [14]3 years ago
5 0


s=-3

<em /><em>10-s=?    </em><u>Substitute s:</u>

10-(-3)=10+3=13

10-s=13

Answer: 13

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The line plot above shows the distance in miles Luna runs each day. What is the difference in distance between the fewest miles
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The answer is 4

Step-by-step explanation:

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Find the next number in the number sequence 1,2,4,8,16,...<br> A) 24<br> B) 12<br> C) 20<br> D) 32
Fantom [35]

Answer:

D.

Step-by-step explanation:

To get from 1 to 2 you multiply by 2.

To get from 2 to 4  you multiply by 2.

Notice how each number is multiplied by 2? Now try multiplying 16 times 2 which would be 32.

4 0
3 years ago
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nobodys probably gonna answer this ): but if you can please do with the answers its for my homework :)
kotegsom [21]

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<em>Hope this helps! <3</em>

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6 0
3 years ago
Write a power represented with a positive base and a positive exponent whose value is less then the base
sasho [114]

Answer:

The question is open ended as i suppose since there are infinitely many possibilities. one possible form of the solution can be 5^{2}

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6 0
3 years ago
Determine whether the following series converges or diverges using the integral test. Be sure to verify that the integral test c
Finger [1]

By using the integral test, series converges

What is an integral test for convergence and divergence?

⇒ It is used to prove the divergence or convergence of series. This test is called the integral test, which compares an infinite sum to an improper integral. It is important to note that this test can only be applied when we are considering a series whose terms are all positive.

How to know if a series is converging or diverging?

If the limit exists and is a finite number (a number less than infinity), we say the integral converges. If the limit is ±∞ or does not exist, we say the integral diverges.

let aₓ= f (x) is any function

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\int\limits^\infty_1 {x^{3} /e^{x^4} dx \leq\displaystyle \sum^{\infty}_{k = 1} {x^{3} /e^{x^{4}

and

\int\limits^\infty_1 {x^{3} /e^{x^4} dx=1/4\int\limits^\infty_1 {x^{3} /e^{-u} du

⇒ 1/4 < \infty

So it comes with a finite value hence the series converges

Learn more about the integral tests here :

brainly.com/question/15394015

#SPJ1

4 0
1 year ago
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