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4 years ago

DS=3x+10 and SE=6x-2. What is the value of DE?

Mathematics

1 answer:

Lisa [10]4 years ago

5 0

Answer:

9x+8

Step-by-step explanation:

Given DS = 3x+10 and SE = 6x-2_ the value of DE is expressed as shown;

DE = DS+SE

Substitute the given functions into the formula to get DE

DE = (3x+10)+(6x-2)

Open the parentheses

DE = 3x+10+6x-2

Collect the like terms

DE = 3x+6x+10-2

DE = 9x+8

Hence the value of DE is 9x+8

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