Answer:
5x/3y2
Step-by-step explanation:
Answer:
That sucks.
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
It appears you have vertical angles. The rule with angles is that no matter what, vertical angles are always congruent (or the same). This means you would have to set up the equation to solve for "b" as:
70 - 2b = 28 + 5b
You could solve this manually, but Desmos graphing calculator is faster. Simply type this in and replace b with x and it will give you the answer, which is 6. Hope this helps!
<h3>
Answer:</h3>
y=1/2x
<h3>
Solution:</h3>
- The slopes of perpendicular lines are opposite reciprocals of each other.
- The simplest way to determine a number's reciprocal is to flip it over, like so:
- Now, change the sign:
- So we have the <em>slope </em>of the line that's <em>perpendicular </em>to the given line.
- Now, let's find the line's equation.
- First, let's write it in Point-Slope Form:
- y-y1=m(x-x1)
- y-(-2)=1/2(x-4)
- y+2=1/2x-2 (Point slope)
- Now, convert to slope-intercept:
- y=1/2x+2-2
- y=1/2x
Hope it helps.
Do comment if you have any query.
Answer:
b)(b²-a²)
Step-by-step explanation:
a cotθ + b cosecθ =p
b cotθ + a cosecθ =q
Now,
p²- q²
=(a cotθ + b cosecθ)² - (b cotθ + a cosecθ)² [a²-b²=(a+b)(a-b)]
=(acotθ+bcosecθ + bcotθ+ acosecθ) (a cotθ + bcosecθ -bcotθ-acosecθ)
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ)+b (cosecθ-cotθ)}
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} [a (cotθ-cosecθ) + {- b (cotθ-cosecθ)} ]
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ) - b (cotθ-cosecθ)}
={(cotθ+cosecθ)(a+b)} {(cotθ-cosecθ) (a-b)}
=(cotθ+cosecθ) (a+b) (cotθ-cosecθ) (a-b)
=(cotθ+cosecθ) (cotθ-cosecθ) (a+b) (a-b)
= (cot²θ-cosec²θ) (a²-b²) [(a+b) (a-b)= (a²-b²)]
= -1 . (a²-b²) [ 1+cot²θ=cosec²θ ; ∴cot²θ-cosec²θ=-1]
=(b²-a²)
