Question

A number cube has 6 faces, numbered from 1 to 6. If the cube

Answer 1

$|\Omega|=6^6\\|A|=6\cdot 5^5\\\\P(A)=\dfrac{6\cdot5^5}{6^6}=\dfrac{5^5}{6^5}=\dfrac{3125}{7776}\approx40.2\%$

Answer 2

Answer:

40.2 % to the nearest tenth.

Step-by-step explanation:

Probability( 6 on one roll = 1/6).

Probability (6 on first roll and NOT 6 on the next 5 rolls) = 1/6 * (5/6)^6

= 3125/46656

= 0.06698

Only 1 six rolled can happen in  6 different ways ( where the 6 is on the second, third roll etc.)

So the required probability is 0.06698 * 6 = 0.40188.