Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ = 
L.H.S = sin θ cos θ
so, sin θ cos θ ≠
So, the equation is not a trigonometric identity.
=========================================================
<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
It is a cuz to be a function the x (domain) can only have one y (range) in d it is the number 2 in the 2nd and fourth set of ordered pairs in c it is 3 the first one and the 3rd in b it is -1 its the first and the last one
hope i helped you if u dont mind can i have brainlest <span />
Find the circumference which is 2*3.14*13 and then usethe central angle formula
Answer:
or 
Step-by-step explanation:
we know that
Applying the law of cosines
In this problem we have
c is the length of the third side
Substitute
or 
You can see that each time x increases by 1, y increases by 5. This means that the coefficient of x is 5 (if you graphed it, the slope would be 5). To find what value to add at the end, you can look at what y is when x equals 0. In this case, that is -2 (on a graph, -2 would be the y-intercept).
