All categories

3 years ago

Solve for X 13 6 2x – 18 U 4x - 29 PLEASE HELP!

Mathematics

2 answers:

miskamm [114]3 years ago

8 0

Answer:

x = 15

Step-by-step explanation:

SV = ST + TU + UV , substitute values

4x - 29 = 13 + 6 + 2x - 18 , that is

4x - 29 = 2x + 1 ( subtract 2x from both sides )

2x - 29 = 1 ( add 29 to both sides )

2x = 30 ( divide both sides by 2 )

x = 15

aliya0001 [1]3 years ago

5 0

Answer:

Step-by-step explanation:

,/?

You might be interested in

P(2,-8), Q(8,-8), R(8, -2), S(2,-2) 180° rotation I need help quickly

kompoz [17]

Answer:

P(-2,8) Q(-8,8) R(-8,2) S(-2,2)

Step-by-step explanation: 180 degree rotation rule = (x,y) ---- (-x,-y)

ex : point B (-2, 7) will be B' (2, -7)

6 0

3 years ago

(8x - 35) solve for x

skad [1K]

You must begin by isolating the x.
1. add -35 to the other side of the equation

2. divide by 8 to get x by itself

Hope this helps!

3 0

2 years ago

Solve for d d + 8 < 35

9966 [12]

Answer:

d < 27

Step-by-step explanation:

Solve for d by subtracting 8 from both sides. This isolates d:

d + 8 < 35

-8 -8

------- -------

d < 27

5 0

3 years ago

Show how to solve 2x+5=13, justify the steps

liberstina [14]

Answer:

The answer is 4

Step-by-step explanation:

2x + 5 = 13

Now, Subtract 5 from both side we get,

2x + 5 - 5 = 13 - 5

2x = 8

Then, Divide both side by 2 we get,

2x/2 = 8/2

x = 4

Thus, The answer is 4

-TheUnknownScientist 72

8 0

2 years ago

Read 2 more answers

Suppose we roll a fair six-sided die and sum the values obtained on each roll, stopping once our sum exceeds 307. Approximate th

SOVA2 [1]

Answer:

There is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

Step-by-step explanation:

The roll of a six-sided die sum has this parameters:

Mean: 3.5

Standard deviation: 1.7

If the die is rolled 81 times, the distribution of the sum of the 81 rolls will have the following parameters:

$\mu=n*M=81*3.5=283.5\\\\\sigma=\sqrt{n}s=\sqrt{81}*1.7=9*1.7=15.3$

Note: the variance of the sum of random variables is equal to the sum of the variance of the individual variables.

Then, we can calculate the probabilties that the sum of 81 rolls is lower than 307.

$z=\frac{x-\mu}{\sigma}=\frac{307-283.5}{15.3}= \frac{23.5}{15.3}= 1.536\\\\\\P(x$

There is 94% of chances that the sum of 81 rolls is lower than 307, so there is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

5 0

3 years ago