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elena-s [515]
3 years ago
11

Mandy took a total of 6 quizzes over the course of 3 weeks at this rate, after attending 5 weeks of school this quarter how many

quizzes will mandy have taken?
Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

6 quizzes

Step-by-step explanation:

3 divided by 6 is 2 so 2 quizzes per week. attending two more weeks would add 4 more quizzes. By now mandy will have taken 6 quizzes in five weeks.

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4+(−123). Write your answer as a fraction in simplest form.
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Answer:

-119

Step-by-step explanation:

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The answer is j.
y = |x - 1|
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What is 0.123 rounded to the nearest tenth
Vikentia [17]
0.123\\\\digit\ in\ the\ tenths\ place\ is\ \boxed1

<em>If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).</em>


<em>If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).</em>

0.\underline{1}23\approx\boxed{0.1}

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Pls help ASAP this is due in 1 hour and i can't figure it out! HELPPP
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the area of the surface of this design is 31 in long

4 0
2 years ago
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Ada, Betty, Chris and David have $45 in total Ada gota 52 fromBetty, Chris tripleshis money and Davids money is cut by hall four
andrezito [222]

Using a system of equations, it is found that initially Ada has $0.385.

For the system, we have that the variables are:

  • x is Ada's amount.
  • y is Betty's amount.
  • z is Chris's amount.
  • w is David's amount.

$45 total, hence:

x + y + z + w = 45

Ada <u>gets 2 from Betty</u>, hence:

x + 2 = y - 2

x = y - 4

y = x + 4

<u>Chris triples</u> his money and <u>David's</u> money is <u>cut by half</u> four of them have the same amount, hence:

x + 4 = y = 3z = \frac{w}{2}

Then:

3z = x + 4

z = \frac{x + 4}{3}

x + 4 = \frac{w}{2}

w = 2x + 8

Solving for w, we find Ada's initial amount.

x + y + z + w = 45

x + x + 4 + \frac{x + 4}{3} + 2x + 8 = 45

4x + 12 + \frac{x + 4}{3} = 45

12x + 36 + x + 4 = 45

13x = 5

x = \frac{5}{13}

x = 0.385

Initially, Ada has $0.385.

A similar problem is given at brainly.com/question/6120515

5 0
3 years ago
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