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Ahat [919]
3 years ago
6

Prove that the EOQ cost function can be rewritten as

Mathematics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

the EOQ cost function \mathbf{g(Q)= \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}}

Step-by-step explanation:

Given that:

g(Q) = \dfrac{h}{2 \lambda Q} \begin {pmatrix} Q- \sqrt{\dfrac{2 K \lambda}{h}} \end {pmatrix}^2  + \sqrt{\dfrac{2 Kh}{\lambda}}

Total cost = Purchase Cost + Ordering Cost + Holding Cost

i.e

T = P  \lambda  + h \dfrac{Q}{2}+\dfrac{\lambda K}{Q}

By differentiating with respect to Q and equating to zero, we have:

0 = 0 +\dfrac{h}{2}- \dfrac{\lambda K}{Q^2}

Q* = \sqrt{\dfrac{2 k \lambda}{h}}

Now;

T = P \lambda + \dfrac{h}{2Q}(Q-Q^*)^2 + hQ^*

T = \dfrac{h}{2Q}(Q- \sqrt{\dfrac{2 \lambda K}{h}})^2 + \sqrt{2 hK \lambda } + P \lambda

(\dfrac{T - P \lambda}{\lambda }) = \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}

Therefore:

the EOQ cost function \mathbf{g(Q)= \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}}

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Write the equation of the circle with center (-4, 8) and passes through the point (-2, -1)
anzhelika [568]

Answer:

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Step-by-step explanation:

The standard equation for a circle is given by:

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