Answer:29.15
Step-by-step explanation:
You just divide 21.20 by 8 then multiply
Answer:
The fraction is 1/4
Step-by-step explanation:
we know that
The area of an equilateral triangle, using the law of sines is equal to



where
x is the length side of the triangle
In this problem
Let
b ----> the length side of the regular hexagon
2b ---> the length side of the equilateral triangle
step 1
Find the area of the six triangles
Multiply the area of one triangle by 6
![A=6[x^{2}\frac{\sqrt{3}}{4}]](https://tex.z-dn.net/?f=A%3D6%5Bx%5E%7B2%7D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D)

we have

substitute

step 2
Find the area of the regular hexagon
Remember that, a regular hexagon can be divided into 6 equilateral triangles
so
The area of the regular hexagon is the same that the area of 6 equilateral triangles

we have

substitute

step 3
To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

I found this!!!!
The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.
- The scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).
Step-by-step explanation:
You can observe in the figure attached that "AC" is the distance between the Sun and the shooting star.
Knowing the distance between the Earth and the Sun "y" and the angle x°, the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.
This is:
cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
In this case:
\begin{gathered}\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC\end{gathered}
α=x\°
adjacent=BC=y
hypotenuse=AC
Therefore, the scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
, and solve for the distance between the Sun and the shooting star "AC":
cos(x\°)=\frac{y}{AC}cos(x\°)=
AC
y
AC=\frac{y}{cos(x\°)}AC=
cos(x\°)
y
Quadratic function whose zeros are 5 and -7 is x^2+2x-35=0
Step-by-step explanation:
Write a quadratic function h whose zeros are 5 and -7
If 5 and -7 are zeros of quadratic function then:
x=5 and x=-7
or x-5 = 0 and x+7=0
So, Finding quadratic equation:

So, quadratic function whose zeros are 5 and -7 is x^2+2x-35=0
Keywords: Quadratic Function
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