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Marrrta [24]
3 years ago
11

The difference of two numbers is always less than the sum of those two numbers

Mathematics
1 answer:
densk [106]3 years ago
3 0
<h3>Answer: False</h3>

Here's a counter example to prove the statement to be incorrect

first number = 1

second number = -2

sum = 1 + (-2) = -1

difference = 1 - (-2) = 1 + 2 = 3

We see that the difference (3) is not smaller than the sum (-1)

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I need help with this
Finger [1]

ask your teacher.

use a calculator.

Use math tutoring for this module.

Pay more attention to the lecture.

3 0
3 years ago
Which graph shows the function y = ( 1/3)3x?​
arlik [135]

Answer:

the first one

Step-by-step explanation:

y = 3x/3

y = x

7 0
3 years ago
What is the solution to the system of equations below? y=2/5x-3 and x = –10
Andru [333]

The solution to the system of equations y=\frac{2}{5}x-3\,\,and\,\,x=-10 is (-10,-7)

Option 1 is correct.

Step-by-step explanation:

We need to find the solution to the system of equations below.

y=\frac{2}{5}x-3\,\,and\,\,x=-10

The value of x i s x=-10

Putting value of x in first equation we can find value of y

y=\frac{2}{5}x-3\\y=\frac{2}{5}*-10-3\\y=2*-2-3\\y=-4-3\\y=-7

So, value of y is y=-7

The solution to the system of equations y=\frac{2}{5}x-3\,\,and\,\,x=-10 is (-10,-7)

Option 1 is correct.

Keywords: System of equations

Learn more about system of equations at:

  • brainly.com/question/9045597
  • brainly.com/question/3739260
  • brainly.com/question/13168205

#learnwithBrainly

5 0
3 years ago
Read 2 more answers
Square RSTU is inscribed in circle P. Given the coordinates for the vertices of the square, find the equation of circle P.
svlad2 [7]

Answer:

(x-2)^2+y^2=20

Step-by-step explanation:

We want to find the equation of a circle P, and we know that the square RSTU is inscribed in the circle, this means that if we replace the points:

R(0,4) S(6,2) T(4,-4) and U(-2,-2) the equation must be verified.

Then, we have to replace the points in each option to see which one is the correct answer.

Option A: (x-2)^2+y^2=68

  • R(0,4):

(x-2)^2+y^2=68\\(0-2)^2+4^2=68\\(-2)^2+16=68\\4+16=68\\20\neq 68

We can see that R doesn't belong to the equation of the circle.

We could replace the rest of the points in the equation, but since we already know that R does not belong to the circle, we already know that it is not the right option.

Option B: (x+2)^2+y^2=20

  • R(0,4):

(x+2)^2+y^2=20\\(0+2)^2+4^2=20\\2^2+4^2=20\\4+16=20\\20=20

The point R(0,4) verifies the equation.

  • S(6,2):

(x+2)^2+y^2=20\\(6+2)^2+2^2=20\\8^2+4^2=20\\64+16=20\\80\neq 20

The point S doesn't belong to the equation of the circle, then we already know that this isn't the correct option.

Option C: (x-2)^2+y^2=20

  • R(0,4):

(x-2)^2+y^2=20\\(0-2)^2+4^2=20\\(-2)^2+16=20\\4+16=20\\20=20

The point R verifies the equation.

  • S(6,2):

(x-2)^2+y^2=20\\(6-2)^2+2^2=20\\4^2+4=20\\16+4=20\\20=20

The point S verifies the equation.

  • T(4,-4):

(x-2)^2+y^2=20\\(4-2)^2+(-4)^2=20\\2^2+16=20\\4+16=20\\20=20

The point T verifies the equation.

  • U(-2,-2):

(x-2)^2+y^2=20\\(-2-2)^2+(-2)^2=20\\(-4)^2+4=20\\16+4=20\\20=20

The point U verifies the equation.

<em>We can see that the four points RSTU verifies the equation. This means that the square RSTU is inscribed in circle P whose equation is: </em>(x-2)^2+y^2=20

<em>We can see that the graph of the equation verifies the answer.</em>

3 0
3 years ago
Find the area of the figure. Round to the nearest tenth if necessary.
Anestetic [448]
So I went ahead and divided up the figure so that you would understand what I'm going to tell you. Let's start with the red rectangle.

The distance from point R to point I is 6 units and the distance from Point R to point S is 5 units. 6*5 = 30 so that red rectangle has an area of 30 units

Now let's calculate triangle AVI. Area of a triangle is Base * Height. The base is 1 and the height is 5 which means the area of triangle AVI is 5.

Next, triangle ALT. From Point A to point L is 4 unit. From Point L to point T is 3 units. 4*3 is 12. So triangle ALT has an area of 12.

Triangle TSI. From Point T to point L is 3 units. From Point L to X is 2. Triangle TSI has an area of 6.

Now we add all of them up. 30+5+12+6 = 53. In total, RSTUV has an area of 53

8 0
3 years ago
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