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mylen [45]
1 year ago
12

1. Which of the following situations could be represented by the equation y = -2x + 88?

Mathematics
2 answers:
SVETLANKA909090 [29]1 year ago
7 0
The answer is C because 88 is the amount you cannot change and the slope is negative, therefore it makes the most sense for it to be connected with the questions that Priscilla misses.
Degger [83]1 year ago
3 0

the answer is c. 88
(:
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How do you find the area of this
zlopas [31]

Answer:

2345 units^2

Step-by-step explanation:

First, you can use Soh Cah Toa to find line c to be 36*sqrt(2). Furthermore, you can use the same equation to find the other sides to be both 65.15. To further solve, you just need to multiply 65.15 by 36 to get a final answer of 2,345.4 units^2

<em>Please Mark Brainliest if this helped!</em>

5 0
4 years ago
Ryan has 4 cups of grape juice, and Kelsey has 7 cups of lemonade. They want to combine what they have to make punch. How many 1
BaLLatris [955]
16 1/2 cup servings if they are putting the grape juice and the lemonade together then that adds up to be 8 and then you have to fine how many 1/2 cups you can get out of 8 which is going to be twice as much so it's 16
7 0
3 years ago
Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
4 years ago
How to graph the function f(x)=-2(x+3) +4
Paraphin [41]

Answer:

Step-by-step explanation:

first of all, simplify your fraction. f(x)= -2(x+3) + 4

                                                     f(x)= (-2x-6) + 4

                                                     f(x)= -2x-2

y intercept is -2 and the slope is -2, go down 2 and right 1

3 0
3 years ago
Perimeter of a triangle with side length of 13.9in,10.4,8.5in
AlladinOne [14]

Perimeter =a+b+c

13.9 + 10.4 + 8.5 =

32.8 in (perimeter)


6 0
3 years ago
Read 2 more answers
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