If the circle diam. is 100 ft., then the radius is 50 ft.
Assuming that the center of the circular cross section is at the origin, the equation of this circle of radius 50 ft. is
x^2 + y^2 = (50 ft)^2 (answer)
Answer:
(E) I, II and III
Step-by-step explanation:
Given,
[email protected] = a + b - ab ∀ a, b ∈ Z ( set of all integers ),
For solving this question we need to remember the following properties of integers:
I. [email protected] = a + b - ab,
[email protected] = b + a - ba = a + b - ab
Thus, [email protected] = [email protected]
II. [email protected] = a + 0 - a × 0
= a + 0 - 0
= a
III. ([email protected])@c = ([email protected])+c - ([email protected])c
= (a + b - ab) + c - (a + b - ab)c
= a + b - ab + c - ac - bc + abc
= a + b + c - ab - bc - ac + abc,
Now, [email protected]([email protected]) = [email protected]( b + c - bc )
= a + (b + c - bc) - a(b+c - bc)
= a + b + c - bc - ab - ac + abc
= a + b + c - ab - bc - ac + abc.
Thus, ([email protected])@c = [email protected]([email protected])
this is prime
k = 13 is the value of k in quartic equation.
What does the term "quartic equation" mean?
An equation of the fourth degree, often known as a quartic equation, is one that reduces a quartic polynomial to zero. in which a 0. A quartic function's derivative is a cubic function.
Let α = 7x
β = 6x
α + β = 7x + 6x = k/3 ............1
13x = k/3
αβ = 7x × 6x = 14/3
42x² = 14/3
x² = 14/3 × 42
x² = 1/9
x = 1/3
now putting value of x in 1
7/3 + 6/3 = k/3
1/3( 7 + 6 )= k/3
k = 13
Learn more about quartic equation
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