Can someone pleaseee help me?!

Max can type 160 words in 5 minutes. How long would it take him to type 400 words? * A. 12.50 minB. 13 minC. 10.50 minD. 12 min

blagie [28]

To find how long it would take him, one has to divide 400 by 160 and then multiply 5 by what that number is. You multiply 5 by the quotient because that is the number that would make it proportional. 400/160 x 5 is 12.5, meaning that the answer is 12.5 minutes, or A.

5 0

3 years ago

During a promotional weekend a state fair gives a free admission to every 175th Person who enters the fair on Saturday there wer

emmasim [6.3K]

Answer:

69

Step-by-step explanation:

If every 175th person gets free admission, that means

175th

175 * 2 = 350th

175 * 3 = 525th

person gets free admission and so on...

This basically means "how many 175s are there is 6742 (for first day) and 5487 (for 2nd day)?"

We would need to divide and see the WHOLE number, not the fractional(decimal) amount remaining. So

1st Day:

6742/175 = 38.53

This means 38 people will get free admission

2nd Day:

5487/175 = 31.35

This means 31 people will get free admission

In the 2 days, total of 38 + 31 = 69 people will get free admission

8 0

3 years ago

A certain disease occurs most frequently among older women. Of all age groups, women in their 60s have the highest rate of breas

Law Incorporation [45]

Answer:

The probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

Step-by-step explanation:

Let a set be events that have occurred be denoted as:

S = {A₁, A₂, A₃,..., Aₙ}

The Bayes' theorem states that the conditional probability of an event, say Aₙ given that another event, say X has already occurred is given by:

$P(A_{n}|X)=\frac{P(X|A_{n})P(A_{n})}{\sum\limits^{n}_{i=1}{P(X|A_{i})P(A_{i})}}$

The disease Breast cancer is being studied among women of age 60s.

Denote the events as follows:

B = a women in their 60s has breast cancer

+ = the mammograms detects the breast cancer

The information provided is:

$P(B) = 0.0312\\P(+|B)=0.81\\P(+|B^{c})=0.92$

Compute the value of P (B|+) using the Bayes' theorem as follows:

$P(B|+)=\frac{P(+|B)P(B)}{P(+|B)P(B)+P(+|B^{c})P(B^{c})}$

$=\frac{(0.81\times 0.0312)}{(0.81\times 0.0312)+(0.92\times (1-0.0312)}\\$

$=\frac{0.025272}{0.025272+0.891296}$

$=0.02757\\\approx0.0276$

Thus, the probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

4 0

3 years ago

Read 2 more answers

Adam got 56 out of 84 correct in his test. What fraction of the marks did he get correct

kondor19780726 [428]

56/84 or 2/3

Hope this helped!

7 0

3 years ago

Read 2 more answers

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

5 0

3 years ago