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4 years ago

4/1000 as a mixed number

Mathematics

2 answers:

jolli1 [7]4 years ago

7 0

Answer:

Step-by-step explanation:

Since 4 /1000 is a proper fraction, it cannot be written as a mixed number.

Cannot be written as a mixed number .

juin [17]4 years ago

4 0

Answer:

You cannot put 4/1000 as a mixed number since it is a proper fraction. You can only reduce the fraction of that is your answer.

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Identify all of the problems that would result in a product of 2 5 ?

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Jackie has 54 fewer beads then sally. If B stands for the number of beats Jackie has, write an expression that represents the nu

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B+54

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If Jackie has B beads, and Sally has 54 more than that, then you are adding 54 to B

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In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from 0 to 10, where 0

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Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(X < 4) = 0.4141$

$P(4 < X < 6) = 0.32876$

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The correct option is B

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 4.5$

The standard deviation is $\sigma = 2.3$

Generally the probability that a randomly selected study participant's response was less than 4 is mathematically represented as

$P(X < 4) = P(\frac{X - \mu }{\sigma} < \frac{4 - 4.5}{ 2.3} )$

$\frac{X -\mu}{\sigma} = Z (The \ standardized \ value \ of\ X )$

$P(X < 4) = P(Z < -0.217 )$

From the z-table $P(Z < -0.217 ) = 0.4141$

$P(X < 4) = 0.4141$

Generally the probability that a randomly selected study participant's response was between 4 and 6 is mathematically represented as

$P(4 < X < 6) = P( < \frac{4 - 4.5}{ 2.3} < \frac{X - \mu }{\sigma} < \frac{6 - 4.5}{2.3})$

=> $P(4 < X < 6) = P( \frac{4 - 4.5}{ 2.3} < \frac{X - \mu }{\sigma} < \frac{6 - 4.5}{2.3})$

=> $P(4 < X < 6) = P( -0.217 < Z< 0.6522$

=> $P(4 < X < 6) = (Z< 0.6522) -P( Z < -0.217)$

From the z-table

$(Z< 0.6522) = 0.74286$

$P(4 < X < 6) = 0.74286 -0.4141$

=> $P(4 < X < 6) = 0.74286 -0.4141$

=> $P(4 < X < 6) = 0.32876$

Generally the probability that a randomly selected study participant's response was more than 8 is mathematically represented as

$P(X > 8) = P(\frac{X - \mu }{\sigma} > \frac{8 - 4.5}{ 2.3} )$

$P(X > 8) = P(Z > 1.52174 )$

From the z-table $P(Z > 1.52174 ) = 0.064037$

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Answer:

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Step-by-step explanation:

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